6(4+y)-3=4(-y-3)+7y

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Solution for 6(4+y)-3=4(-y-3)+7y equation: 



6(4+y)-3=4(-y-3)+7y

We move all terms to the left:

6(4+y)-3-(4(-y-3)+7y)=0

We add all the numbers together, and all the variables

6(y+4)-(4(-1y-3)+7y)-3=0

We multiply parentheses

6y-(4(-1y-3)+7y)+24-3=0



We calculate terms in parentheses: -(4(-1y-3)+7y), so:

4(-1y-3)+7y

We add all the numbers together, and all the variables

7y+4(-1y-3)

We multiply parentheses

7y-4y-12

We add all the numbers together, and all the variables

3y-12

Back to the equation:

-(3y-12)



We add all the numbers together, and all the variables

6y-(3y-12)+21=0

We get rid of parentheses

6y-3y+12+21=0

We add all the numbers together, and all the variables

3y+33=0

We move all terms containing y to the left, all other terms to the right

3y=-33

y=-33/3

y=-11

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