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3(a+1)-5=7a-2
We move all terms to the left:
3(a+1)-5-(7a-2)=0
We multiply parentheses
3a-(7a-2)+3-5=0
We get rid of parentheses
3a-7a+2+3-5=0
We add all the numbers together, and all the variables
-4a=0
a=0/-4
a=0
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