6(3y-1)=-3(3y+2)

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Solution for 6(3y-1)=-3(3y+2) equation: 



6(3y-1)=-3(3y+2)

We move all terms to the left:

6(3y-1)-(-3(3y+2))=0

We multiply parentheses

18y-(-3(3y+2))-6=0



We calculate terms in parentheses: -(-3(3y+2)), so:

-3(3y+2)

We multiply parentheses

-9y-6

Back to the equation:

-(-9y-6)



We get rid of parentheses

18y+9y+6-6=0

We add all the numbers together, and all the variables

27y=0

y=0/27

y=0

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