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4(3x-1)+2=-(x-3)-x
We move all terms to the left:
4(3x-1)+2-(-(x-3)-x)=0
We multiply parentheses
12x-(-(x-3)-x)-4+2=0
We calculate terms in parentheses: -(-(x-3)-x), so:We add all the numbers together, and all the variables
-(x-3)-x
We add all the numbers together, and all the variables
-1x-(x-3)
We get rid of parentheses
-1x-x+3
We add all the numbers together, and all the variables
-2x+3
Back to the equation:
-(-2x+3)
12x-(-2x+3)-2=0
We get rid of parentheses
12x+2x-3-2=0
We add all the numbers together, and all the variables
14x-5=0
We move all terms containing x to the left, all other terms to the right
14x=5
x=5/14
x=5/14
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