6(3y+2)=1

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Solution for 6(3y+2)=1 equation: 



6(3y+2)=1

We move all terms to the left:

6(3y+2)-(1)=0

We multiply parentheses

18y+12-1=0

We add all the numbers together, and all the variables

18y+11=0

We move all terms containing y to the left, all other terms to the right

18y=-11

y=-11/18

y=-11/18

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