If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x^2+40x-2500=0
a = 8; b = 40; c = -2500;
Δ = b2-4ac
Δ = 402-4·8·(-2500)
Δ = 81600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{81600}=\sqrt{1600*51}=\sqrt{1600}*\sqrt{51}=40\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40\sqrt{51}}{2*8}=\frac{-40-40\sqrt{51}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40\sqrt{51}}{2*8}=\frac{-40+40\sqrt{51}}{16} $
| X=7w2+4w−6Y=w2−11w+13 X+Y=X+Y= | | 39-19=x | | 3z+3=4z+8 | | 14=-3x-2((-3x+11) | | 4x-33=75 | | 18×x=200 | | 6/7x-4=26 | | Y=3x±6 | | 9(3x+5)=-54 | | 2.5m+172.2=600 | | 5/12=p=7/12 | | 12+14×h/2=52 | | 15-2b=3 | | 6x+(4x-10)=180 | | 16x^2-96x+45=0 | | 7/3x-5=30 | | -14x+3(2x+5)=-18-7x | | 8y-6+32+90=180 | | 5/7x+1/6x=407 | | -7v=-9v+6 | | 9=3-3t | | .36m+128.88=160.92 | | 12x-1=3x+17 | | X-2(x+3)=2(x+1)-4 | | 4r=5r+1 | | x2x+3=−1 | | 5/7x-6=4 | | 12=15-3y | | -5c+6=-2-4c | | 3=9-2t | | 0.01(5793-470v)=1 | | -5c+6=-2−4c |