6(3x2+4)-10=1/2(4x+16)

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Solution for 6(3x2+4)-10=1/2(4x+16) equation:



6(3x^2+4)-10=1/2(4x+16)
We move all terms to the left:
6(3x^2+4)-10-(1/2(4x+16))=0
Domain of the equation: 2(4x+16))!=0
x∈R
We multiply parentheses
18x^2-(1/2(4x+16))+24-10=0
We multiply all the terms by the denominator
18x^2*2(4x+16))-(1+24*2(4x+16))-10*2(4x+16))=0
We add all the numbers together, and all the variables
18x^2*2(4x+16))-(1+24*2(4x+16))-10*2(4x=0
Wy multiply elements
36x^3(4+96x^2(4=0
We do not support expression: x^3(4

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