4(y-2)=6y+8-2(-3y-1)

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Solution for 4(y-2)=6y+8-2(-3y-1) equation: 



4(y-2)=6y+8-2(-3y-1)

We move all terms to the left:

4(y-2)-(6y+8-2(-3y-1))=0

We multiply parentheses

4y-(6y+8-2(-3y-1))-8=0



We calculate terms in parentheses: -(6y+8-2(-3y-1)), so:

6y+8-2(-3y-1)

determiningTheFunctionDomain
6y-2(-3y-1)+8

We multiply parentheses

6y+6y+2+8

We add all the numbers together, and all the variables

12y+10

Back to the equation:

-(12y+10)



We get rid of parentheses

4y-12y-10-8=0

We add all the numbers together, and all the variables

-8y-18=0

We move all terms containing y to the left, all other terms to the right

-8y=18

y=18/-8

y=-2+1/4

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