3x-7+2(6x+1)=-3(x+1)

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Solution for 3x-7+2(6x+1)=-3(x+1) equation: 



3x-7+2(6x+1)=-3(x+1)

We move all terms to the left:

3x-7+2(6x+1)-(-3(x+1))=0

We multiply parentheses

3x+12x-(-3(x+1))+2-7=0



We calculate terms in parentheses: -(-3(x+1)), so:

-3(x+1)

We multiply parentheses

-3x-3

Back to the equation:

-(-3x-3)



We add all the numbers together, and all the variables

15x-(-3x-3)-5=0

We get rid of parentheses

15x+3x+3-5=0

We add all the numbers together, and all the variables

18x-2=0

We move all terms containing x to the left, all other terms to the right

18x=2

x=2/18

x=1/9

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