6(3x-4)+10=6(x-2)-(3x+4)

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Solution for 6(3x-4)+10=6(x-2)-(3x+4) equation: 



6(3x-4)+10=6(x-2)-(3x+4)

We move all terms to the left:

6(3x-4)+10-(6(x-2)-(3x+4))=0

We multiply parentheses

18x-(6(x-2)-(3x+4))-24+10=0



We calculate terms in parentheses: -(6(x-2)-(3x+4)), so:

6(x-2)-(3x+4)

We multiply parentheses

6x-(3x+4)-12

We get rid of parentheses

6x-3x-4-12

We add all the numbers together, and all the variables

3x-16

Back to the equation:

-(3x-16)



We add all the numbers together, and all the variables

18x-(3x-16)-14=0

We get rid of parentheses

18x-3x+16-14=0

We add all the numbers together, and all the variables

15x+2=0

We move all terms containing x to the left, all other terms to the right

15x=-2

x=-2/15

x=-2/15

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