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-4x^2+10x+24=0
a = -4; b = 10; c = +24;
Δ = b2-4ac
Δ = 102-4·(-4)·24
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-22}{2*-4}=\frac{-32}{-8} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+22}{2*-4}=\frac{12}{-8} =-1+1/2 $
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