6(3x-1)=2x+2(2x-5)-8

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Solution for 6(3x-1)=2x+2(2x-5)-8 equation: 



6(3x-1)=2x+2(2x-5)-8

We move all terms to the left:

6(3x-1)-(2x+2(2x-5)-8)=0

We multiply parentheses

18x-(2x+2(2x-5)-8)-6=0



We calculate terms in parentheses: -(2x+2(2x-5)-8), so:

2x+2(2x-5)-8

We multiply parentheses

2x+4x-10-8

We add all the numbers together, and all the variables

6x-18

Back to the equation:

-(6x-18)



We get rid of parentheses

18x-6x+18-6=0

We add all the numbers together, and all the variables

12x+12=0

We move all terms containing x to the left, all other terms to the right

12x=-12

x=-12/12

x=-1

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