4v2+8v2=0

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Solution for 4v2+8v2=0 equation:



4v^2+8v^2=0
We add all the numbers together, and all the variables
12v^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{0}{24}=0$

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