6(3x+5)-4(2x-6)=40-3(x+8)

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Solution for 6(3x+5)-4(2x-6)=40-3(x+8) equation: 



6(3x+5)-4(2x-6)=40-3(x+8)

We move all terms to the left:

6(3x+5)-4(2x-6)-(40-3(x+8))=0

We multiply parentheses

18x-8x-(40-3(x+8))+30+24=0



We calculate terms in parentheses: -(40-3(x+8)), so:

40-3(x+8)

determiningTheFunctionDomain
-3(x+8)+40

We multiply parentheses

-3x-24+40

We add all the numbers together, and all the variables

-3x+16

Back to the equation:

-(-3x+16)



We add all the numbers together, and all the variables

10x-(-3x+16)+54=0

We get rid of parentheses

10x+3x-16+54=0

We add all the numbers together, and all the variables

13x+38=0

We move all terms containing x to the left, all other terms to the right

13x=-38

x=-38/13

x=-2+12/13

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