7(y-4)-6=-2(-8y+8)-y

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Solution for 7(y-4)-6=-2(-8y+8)-y equation: 



7(y-4)-6=-2(-8y+8)-y

We move all terms to the left:

7(y-4)-6-(-2(-8y+8)-y)=0

We multiply parentheses

7y-(-2(-8y+8)-y)-28-6=0



We calculate terms in parentheses: -(-2(-8y+8)-y), so:

-2(-8y+8)-y

We add all the numbers together, and all the variables

-1y-2(-8y+8)

We multiply parentheses

-1y+16y-16

We add all the numbers together, and all the variables

15y-16

Back to the equation:

-(15y-16)



We add all the numbers together, and all the variables

7y-(15y-16)-34=0

We get rid of parentheses

7y-15y+16-34=0

We add all the numbers together, and all the variables

-8y-18=0

We move all terms containing y to the left, all other terms to the right

-8y=18

y=18/-8

y=-2+1/4

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