6(3x+4)=36(2x-1)

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Solution for 6(3x+4)=36(2x-1) equation: 



6(3x+4)=36(2x-1)

We move all terms to the left:

6(3x+4)-(36(2x-1))=0

We multiply parentheses

18x-(36(2x-1))+24=0



We calculate terms in parentheses: -(36(2x-1)), so:

36(2x-1)

We multiply parentheses

72x-36

Back to the equation:

-(72x-36)



We get rid of parentheses

18x-72x+36+24=0

We add all the numbers together, and all the variables

-54x+60=0

We move all terms containing x to the left, all other terms to the right

-54x=-60

x=-60/-54

x=1+1/9

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