F(t)=16t-4t2

Solution for F(t)=16t-4t2 equation:

(F)=16F-4F^2

We move all terms to the left:

(F)-(16F-4F^2)=0

We get rid of parentheses

4F^2-16F+F=0

We add all the numbers together, and all the variables

4F^2-15F=0

a = 4; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·4·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*4}=\frac{0}{8}
=0
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*4}=\frac{30}{8}
=3+3/4
$