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6(3x+2)-5(6x-1)=6(x-3)-5(7x-6)+6x
We move all terms to the left:
6(3x+2)-5(6x-1)-(6(x-3)-5(7x-6)+6x)=0
We multiply parentheses
18x-30x-(6(x-3)-5(7x-6)+6x)+12+5=0
We calculate terms in parentheses: -(6(x-3)-5(7x-6)+6x), so:We add all the numbers together, and all the variables
6(x-3)-5(7x-6)+6x
We add all the numbers together, and all the variables
6x+6(x-3)-5(7x-6)
We multiply parentheses
6x+6x-35x-18+30
We add all the numbers together, and all the variables
-23x+12
Back to the equation:
-(-23x+12)
-12x-(-23x+12)+17=0
We get rid of parentheses
-12x+23x-12+17=0
We add all the numbers together, and all the variables
11x+5=0
We move all terms containing x to the left, all other terms to the right
11x=-5
x=-5/11
x=-5/11
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