64=(2x*x)/2

Solution for 64=(2x*x)/2 equation:

64=(2x*x)/2

We move all terms to the left:

64-((2x*x)/2)=0

We add all the numbers together, and all the variables

-((+2x*x)/2)+64=0

We multiply all the terms by the denominator


-((+2x*x)+64*2)=0


We calculate terms in parentheses: -((+2x*x)+64*2), so:

(+2x*x)+64*2

We add all the numbers together, and all the variables

(+2x*x)+128

We get rid of parentheses

2x*x+128

Wy multiply elements

2x^2+128

Back to the equation:

-(2x^2+128)


We get rid of parentheses

-2x^2-128=0

a = -2; b = 0; c = -128;
Δ = b2-4ac
Δ = 02-4·(-2)·(-128)
Δ = -1024
Delta is less than zero, so there is no solution for the equation