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6(3x+2)+5(7x-6)-12=5(6x-1)+6(x-3)
We move all terms to the left:
6(3x+2)+5(7x-6)-12-(5(6x-1)+6(x-3))=0
We multiply parentheses
18x+35x-(5(6x-1)+6(x-3))+12-30-12=0
We calculate terms in parentheses: -(5(6x-1)+6(x-3)), so:We add all the numbers together, and all the variables
5(6x-1)+6(x-3)
We multiply parentheses
30x+6x-5-18
We add all the numbers together, and all the variables
36x-23
Back to the equation:
-(36x-23)
53x-(36x-23)-30=0
We get rid of parentheses
53x-36x+23-30=0
We add all the numbers together, and all the variables
17x-7=0
We move all terms containing x to the left, all other terms to the right
17x=7
x=7/17
x=7/17
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