59+(3x-27)=4x+(13-2x)

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Solution for 59+(3x-27)=4x+(13-2x) equation: 



59+(3x-27)=4x+(13-2x)

We move all terms to the left:

59+(3x-27)-(4x+(13-2x))=0

We add all the numbers together, and all the variables

(3x-27)-(4x+(-2x+13))+59=0

We get rid of parentheses

3x-(4x+(-2x+13))-27+59=0



We calculate terms in parentheses: -(4x+(-2x+13)), so:

4x+(-2x+13)

We get rid of parentheses

4x-2x+13

We add all the numbers together, and all the variables

2x+13

Back to the equation:

-(2x+13)



We add all the numbers together, and all the variables

3x-(2x+13)+32=0

We get rid of parentheses

3x-2x-13+32=0

We add all the numbers together, and all the variables

x+19=0

We move all terms containing x to the left, all other terms to the right

x=-19

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