6(3v-5)=4(4v+2)

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Solution for 6(3v-5)=4(4v+2) equation: 



6(3v-5)=4(4v+2)

We move all terms to the left:

6(3v-5)-(4(4v+2))=0

We multiply parentheses

18v-(4(4v+2))-30=0



We calculate terms in parentheses: -(4(4v+2)), so:

4(4v+2)

We multiply parentheses

16v+8

Back to the equation:

-(16v+8)



We get rid of parentheses

18v-16v-8-30=0

We add all the numbers together, and all the variables

2v-38=0

We move all terms containing v to the left, all other terms to the right

2v=38

v=38/2

v=19

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