52-(3c+4)=4(c+6)-c

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Solution for 52-(3c+4)=4(c+6)-c equation: 



52-(3c+4)=4(c+6)-c

We move all terms to the left:

52-(3c+4)-(4(c+6)-c)=0

We get rid of parentheses

-3c-(4(c+6)-c)-4+52=0



We calculate terms in parentheses: -(4(c+6)-c), so:

4(c+6)-c

We add all the numbers together, and all the variables

-1c+4(c+6)

We multiply parentheses

-1c+4c+24

We add all the numbers together, and all the variables

3c+24

Back to the equation:

-(3c+24)



We add all the numbers together, and all the variables

-3c-(3c+24)+48=0

We get rid of parentheses

-3c-3c-24+48=0

We add all the numbers together, and all the variables

-6c+24=0

We move all terms containing c to the left, all other terms to the right

-6c=-24

c=-24/-6

c=+4

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