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6(3v+5)=2(6v-21)
We move all terms to the left:
6(3v+5)-(2(6v-21))=0
We multiply parentheses
18v-(2(6v-21))+30=0
We calculate terms in parentheses: -(2(6v-21)), so:We get rid of parentheses
2(6v-21)
We multiply parentheses
12v-42
Back to the equation:
-(12v-42)
18v-12v+42+30=0
We add all the numbers together, and all the variables
6v+72=0
We move all terms containing v to the left, all other terms to the right
6v=-72
v=-72/6
v=-12
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