28-4(d+3)=2(2d+4)

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Solution for 28-4(d+3)=2(2d+4) equation: 



28-4(d+3)=2(2d+4)

We move all terms to the left:

28-4(d+3)-(2(2d+4))=0

We multiply parentheses

-4d-(2(2d+4))-12+28=0



We calculate terms in parentheses: -(2(2d+4)), so:

2(2d+4)

We multiply parentheses

4d+8

Back to the equation:

-(4d+8)



We add all the numbers together, and all the variables

-4d-(4d+8)+16=0

We get rid of parentheses

-4d-4d-8+16=0

We add all the numbers together, and all the variables

-8d+8=0

We move all terms containing d to the left, all other terms to the right

-8d=-8

d=-8/-8

d=1

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