6(3t+2)+10=5(t-2)-(3t+4)

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Solution for 6(3t+2)+10=5(t-2)-(3t+4) equation: 



6(3t+2)+10=5(t-2)-(3t+4)

We move all terms to the left:

6(3t+2)+10-(5(t-2)-(3t+4))=0

We multiply parentheses

18t-(5(t-2)-(3t+4))+12+10=0



We calculate terms in parentheses: -(5(t-2)-(3t+4)), so:

5(t-2)-(3t+4)

We multiply parentheses

5t-(3t+4)-10

We get rid of parentheses

5t-3t-4-10

We add all the numbers together, and all the variables

2t-14

Back to the equation:

-(2t-14)



We add all the numbers together, and all the variables

18t-(2t-14)+22=0

We get rid of parentheses

18t-2t+14+22=0

We add all the numbers together, and all the variables

16t+36=0

We move all terms containing t to the left, all other terms to the right

16t=-36

t=-36/16

t=-2+1/4

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