6(3c+4)=2(8c+5)

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Solution for 6(3c+4)=2(8c+5) equation: 



6(3c+4)=2(8c+5)

We move all terms to the left:

6(3c+4)-(2(8c+5))=0

We multiply parentheses

18c-(2(8c+5))+24=0



We calculate terms in parentheses: -(2(8c+5)), so:

2(8c+5)

We multiply parentheses

16c+10

Back to the equation:

-(16c+10)



We get rid of parentheses

18c-16c-10+24=0

We add all the numbers together, and all the variables

2c+14=0

We move all terms containing c to the left, all other terms to the right

2c=-14

c=-14/2

c=-7

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