3x-2=(3x+1.5)-(x+0.5)

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Solution for 3x-2=(3x+1.5)-(x+0.5) equation:



3x-2=(3x+1.5)-(x+0.5)
We move all terms to the left:
3x-2-((3x+1.5)-(x+0.5))=0
We calculate terms in parentheses: -((3x+1.5)-(x+0.5)), so:
(3x+1.5)-(x+0.5)
We get rid of parentheses
3x-x+1.5-0.5
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
We get rid of parentheses
3x-2x-1-2=0
We add all the numbers together, and all the variables
x-3=0
We move all terms containing x to the left, all other terms to the right
x=3

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