6(3c+2)=48

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Solution for 6(3c+2)=48 equation: 



6(3c+2)=48

We move all terms to the left:

6(3c+2)-(48)=0

We multiply parentheses

18c+12-48=0

We add all the numbers together, and all the variables

18c-36=0

We move all terms containing c to the left, all other terms to the right

18c=36

c=36/18

c=2

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