5(5y-2)+4(2y+6)=25(3y+2)-18y

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Solution for 5(5y-2)+4(2y+6)=25(3y+2)-18y equation:



5(5y-2)+4(2y+6)=25(3y+2)-18y
We move all terms to the left:
5(5y-2)+4(2y+6)-(25(3y+2)-18y)=0
We multiply parentheses
25y+8y-(25(3y+2)-18y)-10+24=0
We calculate terms in parentheses: -(25(3y+2)-18y), so:
25(3y+2)-18y
We add all the numbers together, and all the variables
-18y+25(3y+2)
We multiply parentheses
-18y+75y+50
We add all the numbers together, and all the variables
57y+50
Back to the equation:
-(57y+50)
We add all the numbers together, and all the variables
33y-(57y+50)+14=0
We get rid of parentheses
33y-57y-50+14=0
We add all the numbers together, and all the variables
-24y-36=0
We move all terms containing y to the left, all other terms to the right
-24y=36
y=36/-24
y=-1+1/2

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