6(3c+1)-6(c+2)=-42

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Solution for 6(3c+1)-6(c+2)=-42 equation: 



6(3c+1)-6(c+2)=-42

We move all terms to the left:

6(3c+1)-6(c+2)-(-42)=0

We add all the numbers together, and all the variables

6(3c+1)-6(c+2)+42=0

We multiply parentheses

18c-6c+6-12+42=0

We add all the numbers together, and all the variables

12c+36=0

We move all terms containing c to the left, all other terms to the right

12c=-36

c=-36/12

c=-3

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