4a-4(4a-5)=44

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Solution for 4a-4(4a-5)=44 equation: 



4a-4(4a-5)=44

We move all terms to the left:

4a-4(4a-5)-(44)=0

We multiply parentheses

4a-16a+20-44=0

We add all the numbers together, and all the variables

-12a-24=0

We move all terms containing a to the left, all other terms to the right

-12a=24

a=24/-12

a=-2

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