6(3-z)5=z

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Solution for 6(3-z)5=z equation: 



6(3-z)5=z

We move all terms to the left:

6(3-z)5-(z)=0

We add all the numbers together, and all the variables

6(-1z+3)5-z=0

We add all the numbers together, and all the variables

-1z+6(-1z+3)5=0

We multiply parentheses

-1z-30z+90=0

We add all the numbers together, and all the variables

-31z+90=0

We move all terms containing z to the left, all other terms to the right

-31z=-90

z=-90/-31

z=2+28/31

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