4(y-4)-6=-3(-5y+4)-3y

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Solution for 4(y-4)-6=-3(-5y+4)-3y equation: 



4(y-4)-6=-3(-5y+4)-3y

We move all terms to the left:

4(y-4)-6-(-3(-5y+4)-3y)=0

We multiply parentheses

4y-(-3(-5y+4)-3y)-16-6=0



We calculate terms in parentheses: -(-3(-5y+4)-3y), so:

-3(-5y+4)-3y

We add all the numbers together, and all the variables

-3y-3(-5y+4)

We multiply parentheses

-3y+15y-12

We add all the numbers together, and all the variables

12y-12

Back to the equation:

-(12y-12)



We add all the numbers together, and all the variables

4y-(12y-12)-22=0

We get rid of parentheses

4y-12y+12-22=0

We add all the numbers together, and all the variables

-8y-10=0

We move all terms containing y to the left, all other terms to the right

-8y=10

y=10/-8

y=-1+1/4

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