6(3-x)+(-20)=3(4x+2)

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Solution for 6(3-x)+(-20)=3(4x+2) equation: 



6(3-x)+(-20)=3(4x+2)

We move all terms to the left:

6(3-x)+(-20)-(3(4x+2))=0

We add all the numbers together, and all the variables

6(-1x+3)-(3(4x+2))+(-20)=0

We add all the numbers together, and all the variables

6(-1x+3)-(3(4x+2))-20=0

We multiply parentheses

-6x-(3(4x+2))+18-20=0



We calculate terms in parentheses: -(3(4x+2)), so:

3(4x+2)

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We add all the numbers together, and all the variables

-6x-(12x+6)-2=0

We get rid of parentheses

-6x-12x-6-2=0

We add all the numbers together, and all the variables

-18x-8=0

We move all terms containing x to the left, all other terms to the right

-18x=8

x=8/-18

x=-4/9

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