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21/5x-5=2(12/5x+3)
We move all terms to the left:
21/5x-5-(2(12/5x+3))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x+3))!=0We calculate fractions
x∈R
105x/25x^2+(-(2(12*5x)/25x^2-5=0
We add all the numbers together, and all the variables
105x/25x^2+(-(2(+12*5x)/25x^2-5=0
We calculate fractions
We do not support expression: x^4
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