6(3-d)+2(d)=24

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Solution for 6(3-d)+2(d)=24 equation: 



6(3-d)+2(d)=24

We move all terms to the left:

6(3-d)+2(d)-(24)=0

We add all the numbers together, and all the variables

6(-1d+3)+2d-24=0

We add all the numbers together, and all the variables

2d+6(-1d+3)-24=0

We multiply parentheses

2d-6d+18-24=0

We add all the numbers together, and all the variables

-4d-6=0

We move all terms containing d to the left, all other terms to the right

-4d=6

d=6/-4

d=-1+1/2

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