(3x+12)+(4x-20)=90

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Solution for (3x+12)+(4x-20)=90 equation: 



(3x+12)+(4x-20)=90

We move all terms to the left:

(3x+12)+(4x-20)-(90)=0

We get rid of parentheses

3x+4x+12-20-90=0

We add all the numbers together, and all the variables

7x-98=0

We move all terms containing x to the left, all other terms to the right

7x=98

x=98/7

x=14

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