6(3+c)=5(1+c)

Solution for 6(3+c)=5(1+c) equation:

6(3+c)=5(1+c)

We move all terms to the left:

6(3+c)-(5(1+c))=0

We add all the numbers together, and all the variables

6(c+3)-(5(c+1))=0

We multiply parentheses

6c-(5(c+1))+18=0


We calculate terms in parentheses: -(5(c+1)), so:

5(c+1)

We multiply parentheses

5c+5

Back to the equation:

-(5c+5)


We get rid of parentheses

6c-5c-5+18=0

We add all the numbers together, and all the variables

c+13=0

We move all terms containing c to the left, all other terms to the right

c=-13