3y+3(y-2)=30

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Solution for 3y+3(y-2)=30 equation: 



3y+3(y-2)=30

We move all terms to the left:

3y+3(y-2)-(30)=0

We multiply parentheses

3y+3y-6-30=0

We add all the numbers together, and all the variables

6y-36=0

We move all terms containing y to the left, all other terms to the right

6y=36

y=36/6

y=6

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