6(3+5y)-(2+7y)=5(4+3y)

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Solution for 6(3+5y)-(2+7y)=5(4+3y) equation:



6(3+5y)-(2+7y)=5(4+3y)
We move all terms to the left:
6(3+5y)-(2+7y)-(5(4+3y))=0
We add all the numbers together, and all the variables
6(5y+3)-(7y+2)-(5(3y+4))=0
We multiply parentheses
30y-(7y+2)-(5(3y+4))+18=0
We get rid of parentheses
30y-7y-(5(3y+4))-2+18=0
We calculate terms in parentheses: -(5(3y+4)), so:
5(3y+4)
We multiply parentheses
15y+20
Back to the equation:
-(15y+20)
We add all the numbers together, and all the variables
23y-(15y+20)+16=0
We get rid of parentheses
23y-15y-20+16=0
We add all the numbers together, and all the variables
8y-4=0
We move all terms containing y to the left, all other terms to the right
8y=4
y=4/8
y=1/2

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