6y-(y+8)-3(2-y)=2

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Solution for 6y-(y+8)-3(2-y)=2 equation: 



6y-(y+8)-3(2-y)=2

We move all terms to the left:

6y-(y+8)-3(2-y)-(2)=0

We add all the numbers together, and all the variables

6y-(y+8)-3(-1y+2)-2=0

We multiply parentheses

6y-(y+8)+3y-6-2=0

We get rid of parentheses

6y-y+3y-8-6-2=0

We add all the numbers together, and all the variables

8y-16=0

We move all terms containing y to the left, all other terms to the right

8y=16

y=16/8

y=2

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