6(2z-2)=24

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Solution for 6(2z-2)=24 equation: 



6(2z-2)=24

We move all terms to the left:

6(2z-2)-(24)=0

We multiply parentheses

12z-12-24=0

We add all the numbers together, and all the variables

12z-36=0

We move all terms containing z to the left, all other terms to the right

12z=36

z=36/12

z=3

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