3x-2(4x+5)=6(2-x)+x

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Solution for 3x-2(4x+5)=6(2-x)+x equation: 



3x-2(4x+5)=6(2-x)+x

We move all terms to the left:

3x-2(4x+5)-(6(2-x)+x)=0

We add all the numbers together, and all the variables

3x-2(4x+5)-(6(-1x+2)+x)=0

We multiply parentheses

3x-8x-(6(-1x+2)+x)-10=0



We calculate terms in parentheses: -(6(-1x+2)+x), so:

6(-1x+2)+x

We add all the numbers together, and all the variables

x+6(-1x+2)

We multiply parentheses

x-6x+12

We add all the numbers together, and all the variables

-5x+12

Back to the equation:

-(-5x+12)



We add all the numbers together, and all the variables

-5x-(-5x+12)-10=0

We get rid of parentheses

-5x+5x-12-10=0

We add all the numbers together, and all the variables

-22!=0

There is no solution for this equation

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