6(2y)+2(+20)=40

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Solution for 6(2y)+2(+20)=40 equation: 



6(2y)+2(+20)=40

We move all terms to the left:

6(2y)+2(+20)-(40)=0

determiningTheFunctionDomain
62y-40+2(+20)=0

We add all the numbers together, and all the variables

62y-40+220=0

We add all the numbers together, and all the variables

62y+180=0

We move all terms containing y to the left, all other terms to the right

62y=-180

y=-180/62

y=-2+28/31

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