4z-4=5(2z-8)

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Solution for 4z-4=5(2z-8) equation: 



4z-4=5(2z-8)

We move all terms to the left:

4z-4-(5(2z-8))=0



We calculate terms in parentheses: -(5(2z-8)), so:

5(2z-8)

We multiply parentheses

10z-40

Back to the equation:

-(10z-40)



We get rid of parentheses

4z-10z+40-4=0

We add all the numbers together, and all the variables

-6z+36=0

We move all terms containing z to the left, all other terms to the right

-6z=-36

z=-36/-6

z=+6

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