6(2x-8)-6=6(x-4)+12

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Solution for 6(2x-8)-6=6(x-4)+12 equation: 



6(2x-8)-6=6(x-4)+12

We move all terms to the left:

6(2x-8)-6-(6(x-4)+12)=0

We multiply parentheses

12x-(6(x-4)+12)-48-6=0



We calculate terms in parentheses: -(6(x-4)+12), so:

6(x-4)+12

We multiply parentheses

6x-24+12

We add all the numbers together, and all the variables

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

12x-(6x-12)-54=0

We get rid of parentheses

12x-6x+12-54=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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