3(m-3)+2=6(3m)-2(2m-1)

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Solution for 3(m-3)+2=6(3m)-2(2m-1) equation: 



3(m-3)+2=6(3m)-2(2m-1)

We move all terms to the left:

3(m-3)+2-(6(3m)-2(2m-1))=0

We multiply parentheses

3m-(63m-2(2m-1))-9+2=0



We calculate terms in parentheses: -(63m-2(2m-1)), so:

63m-2(2m-1)

We multiply parentheses

63m-4m+2

We add all the numbers together, and all the variables

59m+2

Back to the equation:

-(59m+2)



We add all the numbers together, and all the variables

3m-(59m+2)-7=0

We get rid of parentheses

3m-59m-2-7=0

We add all the numbers together, and all the variables

-56m-9=0

We move all terms containing m to the left, all other terms to the right

-56m=9

m=9/-56

m=-9/56

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