6(2x-5)=2(3x+15)

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Solution for 6(2x-5)=2(3x+15) equation: 



6(2x-5)=2(3x+15)

We move all terms to the left:

6(2x-5)-(2(3x+15))=0

We multiply parentheses

12x-(2(3x+15))-30=0



We calculate terms in parentheses: -(2(3x+15)), so:

2(3x+15)

We multiply parentheses

6x+30

Back to the equation:

-(6x+30)



We get rid of parentheses

12x-6x-30-30=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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