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6(2x-5)-3x=-3(x+4)-6
We move all terms to the left:
6(2x-5)-3x-(-3(x+4)-6)=0
We add all the numbers together, and all the variables
-3x+6(2x-5)-(-3(x+4)-6)=0
We multiply parentheses
-3x+12x-(-3(x+4)-6)-30=0
We calculate terms in parentheses: -(-3(x+4)-6), so:We add all the numbers together, and all the variables
-3(x+4)-6
We multiply parentheses
-3x-12-6
We add all the numbers together, and all the variables
-3x-18
Back to the equation:
-(-3x-18)
9x-(-3x-18)-30=0
We get rid of parentheses
9x+3x+18-30=0
We add all the numbers together, and all the variables
12x-12=0
We move all terms containing x to the left, all other terms to the right
12x=12
x=12/12
x=1
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